Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
156 views
in Physics by (115k points)
closed by
The Vander Waal's equation of state for a mole of a real gas is
1. PV = nRT
2. \(\left(P + \dfrac{q}{V^2}\right) (V-b)=RT\)
3. \(\left(P + \dfrac{q}{V^2}\right) = nRT\)
4. \(P = \dfrac{nRT}{V-nb} - \dfrac{n^2 a}{V^2}\)

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 4 : \(P = \dfrac{nRT}{V-nb} - \dfrac{n^2 a}{V^2}\)

CONCEPT:

Vander-Waals equation

  • The equation is basically a modified version of the Ideal Gas Law which states that gases consist of point masses that undergo perfectly elastic collisions.
    • However, this law fails to explain the behavior of real gases. Therefore, the Van der Waals equation was devised and it helps us define the physical state of a real gas.
    • Van der Waals equation is an equation relating the relationship between the pressure, volume, temperature, and amount of real gases. For a real gas containing ‘n’ moles, the equation is written as,

\(\Rightarrow \left ( P+\frac{an^{2}}{V^{2}} \right )\left ( V-nb \right )=nRT\)     -----(1)

Where P, V, T, n are the pressure, volume, temperature, and moles of the gas and  ‘a’ and ‘b’ constants specific to each gas

Rearranging the above equation, we get 

\(P = \dfrac{nRT}{V-nb} - \dfrac{n^2 a}{V^2}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...