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A dentist uses a hand held mirror and places it at a distance of 4 cm in front of a decayed teeth to see it magnified image by four times. The focal length of this mirror is:
1. 5.7 cm
2. 3.2 cm
3. 2.1 cm
4. Insufficient data

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Correct Answer - Option 2 : 3.2 cm

The correct answer is option 2) i.e. 3.2 cm

CONCEPT:

  • Concave mirror: If the inner surface of the spherical mirror is the reflecting surface then it is called a concave mirror. It is also called the converging mirror.
    • The nature of the image formed by a concave mirror is real and inverted except when the object is kept between the focus and pole, where the image is virtual and erect.
  • The relation between object distance (u) and image distance (v) with focal length (f) is given by the mirror equation or mirror formula

\(⇒ \frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)

  • ​Magnification: It is the ratio of the image distance (v) and object distance (u)

​Mathematically it is written as

\(⇒ m = \frac{-v}{u} = \frac{h'}{h}\)

Where h' is the height of the image and h is the height of the object.

CALCULATION:

The mirror used by dentists to obtain a magnified image is a concave mirror.

Given that:

Using sign convention - u, v and f will be negative

Object distance, u = -4 cm

Let image distance be  -v

Magnification, m = 4

\(⇒ m =- \frac{v}{u} =4\)

⇒ v = -4u = -4(4) = -16 cm

Using mirror formula

\( \frac{1}{f} = \frac{1}{v} + \frac{1}{u}\)

⇒ \( \frac{1}{-f} = \frac{1}{-16} + \frac{1}{-4}\)

⇒ \( \frac{1}{-f} = \frac{-20}{64 } =\frac{-5}{16}\)

⇒ \(f = \frac{16}{5} = 3.2 \: cm\)

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