Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
162 views
in General by (115k points)
closed by
Which one of the following equations correctly gives the relationship between the specific gravity of soil grains (G) and the hydraulic gradient (i) to initiate 'quick' condition in sand having a void ratio of 0.5?
1. G = 0.5i + 1
2. G = i + 0.5
3. G = 1.5i + 1
4. G = 1.5i - 1

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 3 : G = 1.5i + 1

Concept:

Quick sand condition:

(i) This process in which soil particles are lifted over the soil mass is called quick sand condition. It is also known as 'boiling of sand' as the surface of sand looks it is boiling.

(ii) At quick sand condition, net effective stress is reduce to zero, i.e.

σ̅  = 0

∴ γ'z = ps = 0     {ps = Seepage pressure}

or, γ'z - izγw = 0

i = icr = γ'/γw

(iii) The hydraulic gradient inder which quick sand condition occurs is termed as critical hydraulic gradient. If void ratio and specific gravity of soil is known, then

\(i = {i_{cr}} = \frac{{\gamma '}}{{{\gamma _w}}} = \frac{{\frac{{\left( {G - 1} \right){\gamma _w}}}{{1 + e}}}}{{{\gamma _w}}}\)  

⇒ \(i = \frac{{\left( {G - 1} \right)}}{{1 + e}}\)

Calculation:

Given,

Void ratio (e) = 0.5

∵ We know that, \(i = \frac{{\left( {G - 1} \right)}}{{1 + e}}\)

⇒ \(i = \frac{{\left( {G - 1} \right)}}{{1 + 0.5}}\)

1.5i = G - 1

G = 1.5i + 1

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...