Correct Answer - Option 2 : 40/9 minutes
Given:
Pipe P + Pipe Q = 120/23 minutes
Pipe S = Pipe P + 12 minutes
Pipe R: Pipe Q = 4 : 5
Pipe Q = 15 minutes
Formula:
If time taken by pipe A to fill tank is ‘a’ minutes and by pipe B is ‘b’ minutes to empty the tank then total time taken to fill the tank t ⇒ (1/ t)= (1/a) - (1/b)
If time taken by pipe A to fill tank is ‘a’ minutes and by pipe B is ‘b’ minutes then total time taken to fill the tank t ⇒ (1/ t) = (1/a) + (1/b)
Calculation:
Let, time taken by pipe P = X
⇒ 23/ 120 = (1/ X) + (1/15)
⇒ 23/ 120 = 15 + X/(15X)
⇒ 345X = 1800 + 120X
⇒ 225X = 1800
⇒ X = 8 minutes
⇒ Time taken by pipe S to drain the water = 20 minutes
⇒ Pipe R: Pipe Q = 4 : 5
Let, time taken by pipe R be Y
⇒ Y : 15 = 4 : 5
⇒ Y = 15 × 4/ 5
⇒ Y = 12 minutes
Now, placing all the values in formula
⇒ 1/ t = (1/8) + (1/15) + (1/12) – (1/20)
⇒ 1/ t = (15 + 8 + 10 – 6)/120
⇒ 1/ t = 27/120
∴ Time taken is 40/ 9 minutes to fill up the whole tank when all pipes are opened.