Data: R = 0.1 Ω, Φm = 6t2 + 7t + 1 mWb, t = 1 s
(i) The induced emf, |e| = \(\cfrac{dΦ_m}{dt}\) = \(\cfrac d{dt}\)(6t2 + 7t + 1)
= (12t + 7) mV
= 12(1) + 7 = 19 mV
(ii) The magnitude of the current = \(\cfrac{[e]}R\)
= \(\cfrac{19mV}{0.1Ω}\) = 190 mA