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If two springs k1 and k2 are placed in parallel, the combined stiffness of spring is
1. k1 + k2
2. k1 + k2 / (k1 k2)
3. (k1 k2) / k1 + k2
4. k1 k2

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Correct Answer - Option 1 : k1 + k2

Explanation:

Springs in Series and Parallel:

1. Springs in Series: If springs are in series, then force in each spring will be equal. Then, total extension,

Δ = Δ1 + Δ2

⇒ \(\frac{P}{{{K_1}}} + \frac{P}{{{K_2}}} = \frac{P}{{{K_{eq}}}}\)

\(\frac{1}{{{k_{eq}}}} = \frac{1}{{{k_1}}} + \frac{1}{{{k_2}}}\)

2. Springs in Parallel: In parallel combination, force developed in each spring will be different but deflection in each spring will be equal.

P = P1 + P2

KeqΔ = K1Δ + K2Δ 

Keq = K1 + K2

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