Correct Answer - Option 1 : k
1 + k
2
Explanation:
Springs in Series and Parallel:
1. Springs in Series: If springs are in series, then force in each spring will be equal. Then, total extension,
Δ = Δ1 + Δ2
⇒ \(\frac{P}{{{K_1}}} + \frac{P}{{{K_2}}} = \frac{P}{{{K_{eq}}}}\)
\(\frac{1}{{{k_{eq}}}} = \frac{1}{{{k_1}}} + \frac{1}{{{k_2}}}\)
2. Springs in Parallel: In parallel combination, force developed in each spring will be different but deflection in each spring will be equal.
P = P1 + P2
KeqΔ = K1Δ + K2Δ
Keq = K1 + K2