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Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively
1. 125
2. 127
3. 129
4. 137

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Correct Answer - Option 2 : 127

Given:

Numbers = 1661, 2045

Remainder = 10, 13

Concept Used:

For greatest divisor we have to find HCF, HCF is the highest common factors of the numbers.

Calculation:

When 1661 is divided by the greatest number, remainder = 10 

The completely divisible number = 1661 – 10

⇒ 1651

When 2045 is divided by the greatest number, remainder = 10

The completely divisible number = 2045 – 13

⇒ 2032

Now, For greatest divisor we have to calculate HCF of 1651 and 2032

1651 = 13 × 127

2032 = 24 × 127

HCF of 1651 and 2032 is 127

∴ 127 is the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively.

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