Correct Answer - Option 4 : 4
Given:
A person has to buy both apples and mangoes
The cost of one apple = Rs. 7/-
The cost of a mango = Rs. 5/-.
The cost price of both mangoes and apples = 38
Calculations:
Let the number of apples be 'x' and mangoes be 'y'
The total cost price of apples = 7x
The total cost price of Mangoes = 5y
7x + 5y = 38
If we assume he bought the maximum number of Apples = 35/7
⇒ 5
At least there will be a minimum number of mangoes
Assume 4 Apples = 4 × 7
⇒ Cost of 4 apples = 28
Remaining amount = 38 - 28
⇒ 10
For 10 rupees we can buy mangoes = 10/5 = 2 mangoes
∴ The number of apples he can buy is 4
