Correct Answer - Option 3 : 4 hours 48 minutes
Given:
Pipe A and pipe B can fill a tank alone in 6 and 8 hours respectively and pipe C can empty the same tank in 12 hours.
Concept Used:
If in x hour a tank is filled by a pipe then in 1 hour the tank will be filled by 1/x part of the tank.
Calculation:
Pipe A can fill 1/6 part of the tank in 1 hour
Pipe B can fill 1/8 part of the tank in 1 hour
Pipe C can empty 1/12 part of the tank in 1 hour
In 1 hour tank will be filled by (1/6 + 1/8 - 1/12) part
⇒ (4 + 3 - 2)/24
⇒ 5/24 part
The tank will be fill in 1/(5/24) = 24/5 hours
⇒ (24/5) × 60 minutes
⇒ 288 minutes
⇒ 4 hour 48 minutes
∴ The tank will be filled in 4 hours 48 minutes.