Correct Answer - Option 2 :
\(\dfrac{1-\sin \phi}{1 + \sin \phi} \ \text{or} \ \tan^2 \left(45^\circ - \dfrac{\phi}{2}\right)\)
Concept:
The active earth pressure of soil at a depth “H” is given by:
pa = kaγH
where,
ka = Active earth pressure coefficient
γ = unit weight of soil
H = Depth of soil strata
\({k_a} = \frac{{1 - \sin \phi }}{{1 + \sin \phi }} = ta{n^2}\left( {{{45}^\circ } - \phi/2 } \right)\)
ϕ = Angle of internal friction of soil