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Two numbers are less than a third number by 25% and 30% respectively. How much percent is the second number less than the first?
1.  \(6\frac{2}{3} \)%
2. 7 \(\frac{3}{7}\)%
3. 7 \(\frac{4}{7}\)%
4. 7 

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Correct Answer - Option 1 :  \(6\frac{2}{3} \)%

Given: 

2 numbers are less than a 3rd number respectively = 25% and 30%

Calculation:

Let the 3rd no. = 100

Then, the 1st number = 75

2nd number = 70 

According to the given part,

Required Percentage = (difference of 2nd number and 1st number ) × 100/1st number 

Then,

(75 - 70) × (100/75)%

⇒ 500/75 = \(6\frac{2}{3} \)%

∴ The required percentage is \(6\frac{2}{3} \)%.

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