Correct Answer - Option 3 : 115 minutes
Given:
X can fill the tanker in 20 minutes and Y can empty it in 30 minutes.
Concept:
If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.
Calculation:
Part of the tanker filled in first 2 minutes
⇒ \(\frac{1}{{20}} - \frac{1}{{30}}{\rm{}} = {\rm{}}\frac{{3 - 2}}{{60}}{\rm{}} = {\rm{}}\frac{1}{{60}}\)
Part of tanker filled in 114 minutes
⇒ \(\frac{{57}}{{60}}\)
⇒ \(\frac{{19}}{{20}}\)
∴ Remaining part of tanker will be filled in 115th minutes.