Question

If the 6-digit number 479xyz is exactly divisible by 7, 11 and 13, then the product of the digits x, y and z will be:
1. 1001
2. 794
3. 252
4. 479

Answer 1

Correct Answer - Option 3 : 252

Given:

Six digit number is 479xyz

Divisible by 7, 11, and 13.

Concept Used:

Any number is divisible by 7, 11, and 13 

If the number is in the form of xyzxyz (repeating form)

Calculation:

479xyz = 479479 

⇒ x = 4, y = 7, and z = 9

⇒ x × y × z = 4 × 7 × 9

⇒ x × y × z = 252

∴ The product of xyz is 252.