Question

 If the speed of machining combined cemented carbide and steel tool is halved, then the tool life changes by (assume Taylor’s exponent = 0.25 for single point turning operation)

1. ​​2 times
2. 4 times
3. 8 times
4. 16 times

Answer 1

Correct Answer - Option 4 : 16 times

Concept:

Taylor’s tool life equation is given by, VTⁿ = C

Where V is the cutting-velocity and T is the tool life, n is Taylor’s exponent and C is constant.

So, we can write V₁T₁ⁿ = V₂T₂ⁿ

Calculation:

Given:

n = 0.25, V₁ = V and V₂ = 0.5V

\(\frac{{{V_1}}}{{{V_2}}} = {\left( {\frac{{{T_2}}}{{{T_1}}}} \right)^n}\)

\(\frac{{V}}{0.5V} = {\left( {\frac{{{T_2}}}{{{T_1}}}} \right)^{0.25}} \Rightarrow {T_2} = 16{T_1}\)