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What is the probability of having 53 Sundays or 53 Mondays in a leap year?
1. 2/7
2. 3/7
3. 4/7
4. 5/7

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Correct Answer - Option 2 : 3/7

Concept:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B

 

Calculations:

A leap year consists of 366 days comprising of 52 weeks and 2 days.

There are 7 possibilities for these 2 extra days. 

(i) Sunday, Monday, 

(ii) Monday, Tuesday, 

(iii) Tuesday, Wednesday, 

(iv) Wednesday, Thursday, 

(v) Thursday, Friday, 

(vi) Friday, Saturday and 

(vii) Saturday, Sunday.

Let us consider two events:  A : the leap year contains 53 Sundays 

B: the leap year contains 53 Mondays. 

Then we have P(A) = 2/7, P(B) = 2/7, P(A ∩ B) = 1/7

Hence, required probability = P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 2/7 + 2/7 - 1/7

= 3/7

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