Question

Mohan starts from a point A at 5 : 00 am at the speed of 20 km per hour and from the same point other Rohan starts at 8 : 00 am at the speed of 60 km per hour. 

Quantity I: If both meet each other at other point C and return immediately towards point A. How much total time the Mohan will take go and return immediately to the point A?

Quantity II: 9 hours 

1. Quantity 1 > Quantity 2
2. Quantity 1 ≥ Quantity 2
3. Quantity 1 < Quantity 2
4. Quantity 1 ≤ Quantity 2
5. Quantity 1 = Quantity 2

Answer 1

Correct Answer - Option 5 : Quantity 1 = Quantity 2

Given:

Speed of mohan = 20 km/hr initially

Speed of rohan = 60 km/hr

Formula used:

Distance = speed × time 

Calculation:

The distance travelled by Mohan in first 3 hours = 3 × 20 = 60 km 

⇒ the relative speed of X and Y = 60 – 20 = 40 km per hour 

⇒ 60 = 40 × y 

⇒ y = 1.5 hours 

⇒ It means after 1.5 hours the Rohan meets Mohan. 

Quantity I:

The total time taken by A to go and return immediately = 3 + 1.5 + 3 + 1.5

⇒ Total time taken = 9 hours 

Quantity II: 9 hours

∴ Quantity I = Quantity II