Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
120 views
in Trigonometry by (240k points)
closed by
Find value of sin 75° cos 15° - cos 75° sin 15°
1. \(\frac {\sqrt 3 + 1}{2}\)
2. \(\frac {\sqrt 3}{2}\)
3. 1
4. 0

1 Answer

0 votes
by (239k points)
selected by
 
Best answer
Correct Answer - Option 2 : \(\frac {\sqrt 3}{2}\)

Concept:

sin x cos y + cos x sin y = sin (x + y)

sin x cos y - cos x sin y = sin (x - y)

Calculation:

Here, we have to find the value of sin 75° cos 15° - cos 75° sin 15°

As we know that, sin x cos y - cos x sin y = sin (x - y)

∴ sin 75° cos 15° - cos 75° sin 15° = sin (75° - 15°)

= sin 60° 

\(\frac {\sqrt 3}{2}\)

Related questions

+1 vote
1 answer
0 votes
1 answer
0 votes
1 answer

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...