Correct Answer - Option 2 : 2
Given:
Eight persons, A, B, C, D, E, F, G and H buy some stuff on different occasions.
1) A buys on the fifth number.
2) Four persons buy between E and F.
3) Neither E nor F buys first or at the last.
S.No.
|
Case 1
|
Case 2
|
1
|
|
|
2
|
E
|
F
|
3
|
|
|
4
|
|
|
5
|
A
|
A
|
6
|
|
|
7
|
F
|
E
|
8
|
|
|
4) B buys just after D.
S.No.
|
Case 1
|
Case 2
|
1
|
|
|
2
|
E
|
F
|
3
|
D
|
D
|
4
|
B
|
B
|
5
|
A
|
A
|
6
|
|
|
7
|
F
|
E
|
8
|
|
|
5) The number of persons who buy between A and D is equal to the number of persons who buy between A and F.
Here, case 2 will be cancelled.
S.No.
|
Person
|
1
|
|
2
|
E
|
3
|
D
|
4
|
B
|
5
|
A
|
6
|
|
7
|
F
|
8
|
|
6) G buys after H but not on the 6th number.
7) C does not buy at the first number.
S.No.
|
Person
|
1
|
H
|
2
|
E
|
3
|
D
|
4
|
B
|
5
|
A
|
6
|
C
|
7
|
F
|
8
|
G
|
So, the above shown arrangement is the final order of persons buying stuff.
S.No.
|
Person
|
Reverse Alphabetical order
|
1
|
H
|
H
|
2
|
E
|
G
|
3
|
D
|
F
|
4
|
B
|
E
|
5
|
A
|
D
|
6
|
C
|
C
|
7
|
F
|
B
|
8
|
G
|
A
|
Hence, had they bought their stuff in reverse alphabetical order, 2 of them would have bought at the same rank as they have bought in actual case.