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A and B are two events such that P(B) = 0.4 and P(A ∪ B) = 0.6 If A and B are independent, then P(A) is
1. \(\frac 12\)
2. \(\frac 13\)
3. \(\frac 23\)
4. \(\frac 2 5\)

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Correct Answer - Option 2 : \(\frac 13\)

Concept:

Independent events:

Two events are independent if the incidence of one event does not affect the probability of the other event.

If A and B are two independent events, then P(A ∩ B) = P(A) × P(B)

 

Calculation:

Given: P(B) = 0.4 and P(A ∪ B) = 0.6

P(A ∪ B) = 0.6

⇒ P(A) + P(B) - P(A ∩ B) = 0.6

⇒ P(A) + P(B) - P(A) × P(B) = 0.6               (∵ A and B are independent events.)

⇒ P(B) + P(A) [1 - P(B)] = 0.6

⇒ 0.4 + P(A) [1 - 0.4] = 0.6

⇒ P(A) × 0.6 = 0.2 

\(\therefore {\rm{P}}\left( {\rm{A}} \right) = \frac{{0.2}}{{0.6}} = \frac{1}{3}\)

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