Correct Answer - Option 1 : Thursday
We’ll divide 2013 in different years
2000 years + 12 years + 2013 ( Jan + Feb + March + April + May + June + July + till 15 august)
There are 3 leap years and 9 non-leap years from 2001 to 2012. Therefore, no. of odd days in this period = 1
Also, 2013 is a non-leap year.
Thus, odd days in the given above years = [0 + 1 + (3 + 0 + 3 + 2 + 3 + 2 + 3 + 1)] mod 7
Total odd days = 18 and 18 ÷ 7 = 4 (remainder)
Days codes:
Sunday – 0
Monday – 1
Tuesday – 2
Wednesday – 3
Thursday – 4
Friday – 5
Saturday – 6
Code 4 is for Thursday.
Hence, “Thursday” is the correct answer.
