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Explain electrical resonance in an LC parallel circuit. Deduce the expression for the resonant frequency of the circuit.

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Consider a capacitor of capacitance C, and an inductor of large self-inductance L and negligible resistance, connected in parallel across a source of sinusoidally alternating emf from below figure. Let the instantaneous value of the applied emf be e = e0 sin ωt

(a) A parallel LC circuit. (b) variations of the current and impedance near the resonant frequency

Let iL and iC be the instantaneous currents through the inductor and capacitor respectively. As the current in the inductor lags behind the emf in phase by π/2 radian,

where XL is the inductive reactance. As the current in the capacitor leads the emf by a phase angle of π/2 radian,

where XC is the capacitive reactance. The instantaneous current drawn from the source is

If XL = XC , i = 0. Thus, no current is drawn from the source if XL = XC . In such a case, alternating current goes on circulating in the LC loop, though no current is supplied by the source. This condition is called parallel resonance and the frequency of ac at which it occurs is called the resonant frequency (fr).

The condition for resonance is

In practice, every inductor possesses some resistance and hence even at resonance, some current is drawn from the source. Also, the resonant frequency is different from that for zero resistence.

The resonance curve shows the variation of current (i) and impedance with the frequency of the ac supply, from figure (b). At resonance the current supplied by the source is minimum and the impedance of the circuit is maximum.

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