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The major loss of energy in long pipes is due to:
1. sudden contraction
2. friction
3. gradual contraction or enlargement
4. sudden enlargement

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Best answer
Correct Answer - Option 2 : friction

Explanation:

Losses in pipe: 2 type

Major loss: Major loss occurs only due to friction.

Minor loss: Depend on different factors.

Major loss: 

Major loss in the pipe due to friction is given by the Darcy-Weisbach equation.

\({h_f} = \frac{{fL{V^2}}}{{2gD}}\)

Here, L = length of pipe

D = dia of pipe

V = mean velocity

f = friction factor (0.02 to 0.04 for metals)

hf = head loss due to friction

Minor loss:

Different type of minor losses in pipe

Losses due to the sudden expansion   \({h_{le}} = \frac{{{{({V_{^1}} - {V_{^2}})}^2}}}{{2g}} = \frac{{{V_1}}}{{2g}}{(1 - \frac{{{A_1}}}{{{A_2}}})^2}\)
Losses due to a sudden contraction

\({h_l} = \frac{{{{({V_c} - {V_2})}^2}}}{{2g}} = \frac{{{V_2}^2}}{{2g}}{(\frac{1}{{{C_c}}} - 1)^2}\)

If Cc is not given then, \({h_l} = \frac{{0.5{V_2}^2}}{{2g}}\)

Losses at the exit of the pipe \({h_l} = \frac{{{V^2}}}{{2g}}\)
Losses at the entrance to the pipe \({h_l} = \frac{{0.5{V^2}}}{{2g}}\)
Losses due to bends

\({h_l} = \frac{{K{V^2}}}{{2g}}\)

K = 1.2 for 90

K= 0.4 for 45

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