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If 2cot3x = sin60° + (1/2) sin30°.sec30° then find the value of x?
1. 30°
2. 10°
3. 20°
4. 50°

1 Answer

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Correct Answer - Option 3 : 20°

Given:

The given expression is 2cot3x = sin60° + (1/2) sin30°.sec30°

Formula Used:

Basic concept of trigonometric ratio and identities

We know that

Sin60° = √3/2, Sin30° = ½, cot 60° = 1/√3 and sec30° = 2/√3

Calculation:

By putting the value of trigonometric angles in the expression

∴ 2cot3x = √3/2 + 1/2 × 1/2 × 2/√3

⇒ 2cot3x = √3/2 + 2/4√3

⇒ 2cot3x = 4/2√3

⇒ cot3x = 1/√3

We know that cot60° = 1/√3

∴ cot3x = cot 60°

⇒ 3x = 60°

⇒ x = 20°

Hence, option (3) is correct

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