Correct Answer - Option 5 : x = y or relationship between x and y can't be established
I. x2 – x – 20 = 0
⇒ x2 – 5x + 4x – 20 = 0
⇒ x (x – 5) + 4 (x – 5) = 0
⇒ (x + 4) (x – 5) = 0
∴ x = 5, – 4
II. y2 + 2y – 15 = 0
⇒ y2 + 5y – 3y – 15 = 0
⇒ y (y + 5) – 3 (y + 5) = 0
⇒ (y – 3) (y + 5) = 0
∴ y = 3, – 5
On comparing the values of x and y,
Value of x
|
Value of y
|
Relation |
5
|
3
|
x > y |
5
|
– 5
|
x > y |
– 4
|
3
|
x < y |
– 4
|
– 5
|
x > y |
∴ x = y or relationship between x and y can't be established