Correct Answer - Option 2 :
\(\frac{pd}{4\sigma}\)
Explanation:
Thin spherical shell:
The hoop stress/longitudinal stress of a spherical shell is given by
\({\sigma _L} = {\sigma _H} = \frac{{pd}}{{4t}}=\sigma\)
where p = pressure applied, d = diameter of shell and t = thickness of the shell
After re-arranging the above equation, we get
\(t=\frac{pd}{4\sigma}\)