Correct Answer - Option 2 :
3 × 109 N/m2
Concept:
The bulk modulus of elasticity of the liquid is given by
\(\rm K = - \dfrac{{{{Δ }}P}}{{\left( {\dfrac{{{{Δ }}V}}{V}} \right)}}\;\)
Calculation:
Given:
P1 = 3 MN/m2, P2 = 6 MN/m2, and ΔV = 0.1%
ΔP = P2 - P1 = 6 – 3 = 3 MN/m2, \(\rm {Δ V\over V}=-0.001\)
\(\rm K = - \dfrac{{3 \times {{10}^6}}}{{ - 0.001}} = 3 \times {10^9}\;N/{m^2}\)