Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
317 views
in Percentage by (72.8k points)
closed by
In two successive years, 100 and 200 students of a school appeared at the final examination. Respectively 80% and 60% of them passed. Find the cumulative passing percentage in 2 years. 
1. 50%
2. 60%
3. 66.67%
4. 65%

1 Answer

0 votes
by (121k points)
selected by
 
Best answer
Correct Answer - Option 3 : 66.67%

GIVEN:

In two successive years, 100 and 200 students of a school appeared at the final examination. Respectively 80% and 60% of them passed.

FORMULA USED:

X% of Y = Y × X/100

CALCULATION:

Total number of students appeared in 2 years = 100 + 200 = 300

And

Total number of passed students in 2 years = 100 × 0.8 + 200 × 0.6

= 80 + 120

= 200

Hence,

Required percentage = [200/300] × 100 = 66.67%

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...