Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.0k views
in Algebra by (72.8k points)
closed by
If (x +(1/x)) = 2, then find the value of (x5 + x4 + x3 + x2 + x + 1)

1 Answer

0 votes
by (121k points)
selected by
 
Best answer
Correct Answer - Option 4 : 6

Given

(x +(1/x)) = 2,

(x5 + x4 + x3 + x2 + x + 1) = ?

Calculation

⇒ (x +(1/x)) = 2

⇒ (x2 + 1)/x = 2

⇒ x2 + 1 = 2x 

⇒ x2 - 2x + 12 = 0

⇒ (x - 1)2 = 0 

⇒ x = 1 

Now, Put the value in the given equation

⇒ (x5 + x4 + x3 + x2 + x + 1) = (15 + 14 + 13 + 12 + 1 + 1)

⇒ (x5 + x4 + x3 + x2 + x + 1) = 6

∴ (x5 + x4 + x3 + x2 + x + 1) = 6 

Alternate method

(x +(1/x)) = 2

In this type of question in which x +(1/x)) = 2,

You can directly put value of x = 1 

When you put x = 1 

⇒ x +(1/x)) = 2 

i.e R.H.S = L.HS

So, put the value of x = 1 in the equation

⇒ (x5 + x4 + x3 + x2 + x + 1) = 6

∴ (x5 + x4 + x3 + x2 + x + 1) = 6

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...