Question

Half the perimeter of a rectangular garden, whose length is 4 m more than its width is 36 m. Find the dimensions of the garden.

Answer 1

Let the width of the garden = x cm 

then its length = x + 4 cm 

Half the perimeter = 1/2 × 2(7+ b) = l + b 

By problem, x + x + 4 = 36 

2x + 4 = 36 

2x = 36 – 4 = 32 

∴ x = 16 and x + 4 = 16 + 4 = 20 

i.e., length = 20 cm and breadth = 16 cm. 

(or) 

Let the breadth be x and length = y 

then x + y = 36 ⇒ x + y = 36 

y = x + 4 ⇒ x – y = -4

The two lines intersect at the point (16, 20) 

i.e., length = 20 cm and the breadth = 16 cm.