Let the first A.P be:
a, a + d, a + 2d, ……..
Second A.P be:
b, b + d, b + 2d, b + 3d, ………
Also, general term, an = a + (n – 1)d
Given that, a100 – b100 = 100
⇒ a + 99d – (b + 99d) = 100
⇒ a – b = 100
Now the difference between their 1000th terms,

∴ The difference between their 1000th terms is (a – b) = 100.
Note: If the common difference for any two A.Ps are equal then difference between nth terms of two A.Ps is same for all natural values of n.