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An object moving with 6m per second execute an acceleration 2 m/s^2 in next 3 seconds. How much distance it covered?

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An object moving with 6m per second execute an acceleration 2 m/s2 in next 3 seconds. How much distance it covered? (s = ut + 1/2 at2)

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u = 6 m/s; t = 3 sec; a = 2 m/s2 

s = ut + 1/2at2 

= 6 × 3 + 1/2 × 2 × 32 

= 18 + 9 = 27 m 

The object covers 27 m in 3 sec.

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