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Expand using suitable identities :  (p + 1)^3

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Expand using suitable identities :  (p + 1)3

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Best answer

(p + 1)3 = (P)3 + 3 (p)2 (1) + 3 (p) (1)2 + (1)3

[ ∵ (x + y)3 = x3 + 3x2y + 3xy2 + y3 ] 

= p3 + 3p2 + 3p + 1

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