Question

In the given figure, it is given that AB = AC; ∠BAC = 36°; ∠ADB = 45° and ∠AEC = 40°. Find ∠EAC.

Answer 1

Given that AB = AC; ∠BAC = 36°, 

∠ADB = 45°, ∠AEC = 40°

In ΔADE 

∠D + ∠A + ∠E = 180° 

45° + ∠A + 40° = 180° 

⇒ ∠A = 180° -85° = 95° 

But ∠A = ∠DAB + 36° + ∠EAC 

95° = 27°, + 36° + ∠EAC 

∴ ∠EAC = 95° – 63° = 32°