Given that AP = 3/7 AB
⇒ 7AP = 3AB
⇒ 7AP = 3(AP + BP)
⇒ 7AP = 3AP + 3BP
⇒ 7AP - 3AP = 3PB
⇒ 4AP = 3PB
⇒ \(\frac{AP}{PB}=\frac34\)
Hence, P dividences AB in the ratio 3: 4
By section formula, the coordinates of point P are
(x, y) = \(\left(\frac{3\times2+4\times-2}{3+4},\frac{3\times-4+4\times-2}{3+4}\right)\)
\(=(\frac{6-8}7,\frac{-12-8}7)\)
\(=(\frac{-2}7,\frac{-20}7)\)