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Evaluate the following and justify your answer.

sec 16° cosec 74° – cot 74° tan 16°.

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Given sec 16° cosec 74° – cot 74° tan 16°

= sec 16° . cosec (90° – 16°) – cot (90° – 16°) . tan 16° 

= sec 16°. sec 16° – tan 16° . tan 16° 

[∵ cosec (90° – θ) = sec θ; cot (90° – θ) — tan θ] 

= sec2 16° – tan2 16° 

= 1 [∵ sec2 θ – tan2 θ = 1]

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