Question

The equation

(cos p - 1)x² + (cos p) x + sin p = 0

in the variable x, has real roots. Then p can take any value in the interval.

(a) (0, 2π)

(b) (-π, 0)

(c) (- π/2, π/2)

(d) (0, π)

Answer 1

Correct option: (d) (0, π)

Explanation:

Since, the given quadratic equation

(cos p - 1)x² + (cos p) x + sin p = 0 has real roots.

Hence, the equation has real roots for 0 < p < π.