Question

The reaction of potassium permanganate with acidified iron (II) sulphate is given below : 2KMnO₄ + 10FeSO₄ + 8H₂SO₄ → K₂SO₄ + 2MnSO₄ + 5 Fe₂ (SO₄ )₃ + 8H₂O.

 If 15.8 g. of potassium permanganate was used in the reaction, calculate the mass of iron (II) sulphate used in the above reaction. (K = 39, Mn = 55, Fe = 56, S = 32, O = 16)

Answer 1

316 g of KMnO₄ used iroln (III) sulphate = 1520 g