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Construct ΔPQR in which QR = 8 cm, ∠B = 60° and AB – AC = 3.5 cm. Read ∠Q = 60°and PQ – PR = 3.5 cm Solution:

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Steps: 

  • Draw QR = 8 cm. 
  • Construct ∠RQX = 300 at Q.
  • Mark a point S on \(\overrightarrow{QX}\) such that QS = PQ  – PR = 3.5 cm
  • Join S, R and draw the perpendicular bisector to \(\overline{QR}\) meeting \(\overrightarrow{QX}\) at P.
  • Join P, R to form the ΔPQR.

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