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In a triangle ABC, 2ac sin 1/2(A - B + C) =

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In a triangle ABC, 2ac sin 1/2(A - B + C) =

(a) a2 + b2 - c2

(b) c2 + a2 - b2

(c) b2 - c2 - a2

(d) c2 - a2 - b2

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1 Answer

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Best answer

Correct option: (b) c2 + a2 - b2

Explanation:

We know that, A + B + C = 180°

= A + C - B = 180 - 2B

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