Question

If the exterior angle of a triangle is 110° and it’s interior opposite angles are x° and (x + 10)°, then find the value of ‘x’.

Answer 1

Given interior opposite angles are x° and (x + 10)°. 

Exterior angle =110°. 

Exterior angle of a triangle is equal to the sum of its opposite interior angles. 

x + x + 10° = 110° 

⇒ 2x + 10°- 10° = 110°- 10° 

⇒ 2x = 100°

⇒ 2x/2 = 100°/2

∴ x = 50°