Question

Subtract 3a + 4b – 2c from 6a – 2b + 3c in row method.

Answer 1

Let A = 6a – 2b + 3c, B = 3a + 4b – 2c 

Subtracting 3a + 4b – 2c from 6a – 2b + 3c is equal to adding additive inverse of 3a + 4b – 2c to 6a – 2b + 3c 

i.e., A – B = A + (-B) 

additive inverse of (3a + 4b – 2c) = – (3a + 4b – 2c) 

= – 3a – 4b + 2c A – B = A + (-B) 

= 6a – 2b + 3c + (- 3a – 4b + 2c) 

= 6a – 2b + 3c – 3a – 4b +2c 

= (6 – 3)a – (2 + 4)b + (3 + 2)c 

Thus, the required answer = 3a – 6b + 5c