∠PMY = ∠QMY = 90°
So, PQ ⊥ XY
1. Draw a line segment PQ of length 4.5 cm.
2. Draw two arcs with centre P and radius > 1/2 PQ on both sides of PQ.
3. Repeat step 2 with centre ‘Q’ intersecting the previous arc at X and Y.
4. Join X and Y and produce it on either sides to form \(\overrightarrow {XY}\).
5. XY is the perpendicular bisector of PQ.