Question

The area of the ∆ XYZ is 12 sq.cm and the height XL is 3 cm, then find base YZ

Answer 1

In ∆ XYZ, Base = YZ, 

Height (XL) = 3 cm, 

Area of the XYZ = 12 sq cm

Area of the ∆XYZ = \(\frac {1}2\) × base × height

= \(\frac {1}2\) × YZ × XL

⇒ 12 = \(\frac {1}2\) × YZ × 3 

⇒ YZ = 12 × \(\frac {2}3\)

So, YZ = 8 cm