Question

The length of rectangular grass land is 55 m and breadth is 45 m in the centre of the grass land two paths of 3 m wide one parallel to the length and another parallel to breadth are situated in such a way that they intersect each other. Find the area of the path.

Answer 1

In fig. ABCD is rectangular grass land. 

Length of ABCD = 55 m 

Breadth of ABCD = 45 m 

Width of path = 3 m 

Area of path EFGH = Length × Width 

= 55 × 3 

= 165 Sq.m

Area of path MNOP

= Breadth × Width 

= 45 × 3 = 135 Sq.m.

Area of common path IJKL (situated on both paths) 

= Width × Width = 3 m × 3 m = 9 Sq.m. 

Area of square IJKL i.e., 9 Sq.m is included in both the paths. So we subtract one time. 

Area of total path = Area of path EFGH + Area of path MNOP – Area of IJKL 

= (165 Sq.m. + 135 Sq.m. – 9 Sq.m.) 

= (300 9) Sq.m. 

= 291 Sq.m.