Radius of circular floor = 42 m
Width around it = 7 m
Radius of outer circle = 42 + 7 = 49 m
Area of outside path = Area of outer circle – Area of inner circle
Area of inner circle = πr2 = \(\frac {22}7\) × 42 × 42
Area of the outer circle = πr2 = \(\frac {22}7\) × 49 × 49
Area of floor = \(\frac {22}7\)(49 × 49 – 42× 42)
= \(\frac {22}7\)(2401 – 1764)
= \(\frac {22}7\)× 637 = 2002 m2
∴ Cost of flooring at the rate of ₹ 150 per sq.m is 2002 × 150 = ₹ 300300