If the probability of winning a game is \( 0.26 \), what is the probability of losing it?

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sushmita0871 · Answer 1 · 2022-04-07T17:11:32+0000

P(A)+P(NOT A)=1

where A is any event,

So in this question

P(losing)=1-P(winning)

=1-0.26

=0.74

Therefore Probability of losing the game is 0.74

AnantShaw · Answer 2 · 2022-04-08T10:22:19+0000

Probability of winning a game is P = 0.26

\(\therefore\) Probability of not winning the game = 1 - p = 1 - 0.26 = 0.74

(\(\because\) P(A) + P(not A)) = 1, for any event A)

Since, for a game, there are only two possibility.

Either you win the game or you lose the game.

\(\therefore\) Probability of losing the game is 0.74.