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Zn |Zn^2+ (a = 0.1M)|| Fe^2+ (a = 0.1M)| Fe. The emf of the above cell is 0.2905V. Equilibrium constant for the cell reaction is

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Zn |Zn2+ (a = 0.1M)|| Fe2+ (a = 0.1M)| Fe.

The emf of the above cell is 0.2905V. Equilibrium constant for the cell reaction is

(a) 100.32/0.0591

(b) 100.32/0.0295

(c) 100.26/0.0295

(d) e0.32/0.295

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The correct option (b) 100.32/0.0295

Explanation:

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