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To a closed system 150 kJ of work is supplied. If the initial volume is 0.6 m3 and pressure of the system changes as p = 8 – 4V, where p is in bar and V is in m3, determine the final volume and pressure of the system

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Amount of work supplied to a closed system = 150 kJ

Initial volume = 0.6 m3 

Pressure-volume relationship, p = 8 – 4V

The work done during the process is given by

But this work is equal to – 150 × 103 J as this work is supplied to the system.

∴ – 150 × 103 = 105[8V2 – 2V22 – 4.08]

or 2V22 – 8V2 + 2.58 = 0

Positive sign is incompatible with the present problem, therefore it is not considered

Final volume, V2 = 0.354 m3.  

and, final pressure, p2 = 8 – 4V = 8 – 4 × 0.354

= 6.584 bar = 6.584 × 105 N/m2 or Pa. 

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