Question

The Edison storage cell is represented as : 

Fe(s)/ FeO(s) /KOH(aq)/Ni₂O₃(s)/Ni(s) 

The half-cell reactions are :

Ni₂O₃(s) + H₂O(l) + 2e^- ⇋ 2NiO(s) + 2OH^-

E° = + 0.40V

FeO(s) + H₂O(l) + 2e^-  ⇋ Fe(s) + 2OH^-

E° = - 0.87V

(i) What is the cell reaction? 

(ii) What is the cell emf? How does it depend on the concentration of KOH? 

(iii) What is the maximum amount of electrical energy that can be obtained from one mole of Ni₂O₃?

Answer 1

Given that,

(iii) Produced electrical energy with one mole of