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(a) 1.22g C6H5COOH is added into two solvents and data of ΔTb and Kb are given as:

(i) in 100g CH3COCH3 ΔTb = 0.17,

Kb = 1.7kgK/mol

(ii) In 100g benzene, ΔTb = 0.13 and 

Kb = 2.6kg K/mol

Find out the molecular weight of C6H5COOH in both the cases and interpret the result.

(b) 0.1M of HA is titrated with 0.1M NaOH, calculate the pH at point. Given, Ka(HA) = 5.6 x 10-6 and α <<1.

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(a) (i) In first case

The conclusion is that benzoic acid dimerises in benzene as

Thus at end point the solution contains only Na A (being salt of weak acid and strong base) whose concentration is 0.05M.

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