(a) 1.22g C6H5COOH is added into two solvents and data of ΔTb and Kb are given as:
(i) in 100g CH3COCH3 ΔTb = 0.17,
Kb = 1.7kgK/mol
(ii) In 100g benzene, ΔTb = 0.13 and
Kb = 2.6kg K/mol
Find out the molecular weight of C6H5COOH in both the cases and interpret the result.
(b) 0.1M of HA is titrated with 0.1M NaOH, calculate the pH at point. Given, Ka(HA) = 5.6 x 10-6 and α <<1.